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5-3x=8x^2
We move all terms to the left:
5-3x-(8x^2)=0
determiningTheFunctionDomain -8x^2-3x+5=0
a = -8; b = -3; c = +5;
Δ = b2-4ac
Δ = -32-4·(-8)·5
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-13}{2*-8}=\frac{-10}{-16} =5/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+13}{2*-8}=\frac{16}{-16} =-1 $
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